Optimal. Leaf size=121 \[ -\frac{1}{2} i b d \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )+\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{i d \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}+d \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{1}{4} b c d x \sqrt{1-c^2 x^2}-\frac{1}{4} b d \sin ^{-1}(c x) \]
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Rubi [A] time = 0.116377, antiderivative size = 121, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.348, Rules used = {4683, 4625, 3717, 2190, 2279, 2391, 195, 216} \[ -\frac{1}{2} i b d \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )+\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{i d \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}+d \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{1}{4} b c d x \sqrt{1-c^2 x^2}-\frac{1}{4} b d \sin ^{-1}(c x) \]
Antiderivative was successfully verified.
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Rule 4683
Rule 4625
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rule 195
Rule 216
Rubi steps
\begin{align*} \int \frac{\left (d-c^2 d x^2\right ) \left (a+b \sin ^{-1}(c x)\right )}{x} \, dx &=\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )+d \int \frac{a+b \sin ^{-1}(c x)}{x} \, dx-\frac{1}{2} (b c d) \int \sqrt{1-c^2 x^2} \, dx\\ &=-\frac{1}{4} b c d x \sqrt{1-c^2 x^2}+\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )+d \operatorname{Subst}\left (\int (a+b x) \cot (x) \, dx,x,\sin ^{-1}(c x)\right )-\frac{1}{4} (b c d) \int \frac{1}{\sqrt{1-c^2 x^2}} \, dx\\ &=-\frac{1}{4} b c d x \sqrt{1-c^2 x^2}-\frac{1}{4} b d \sin ^{-1}(c x)+\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{i d \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}-(2 i d) \operatorname{Subst}\left (\int \frac{e^{2 i x} (a+b x)}{1-e^{2 i x}} \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{1}{4} b c d x \sqrt{1-c^2 x^2}-\frac{1}{4} b d \sin ^{-1}(c x)+\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{i d \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}+d \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-(b d) \operatorname{Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{1}{4} b c d x \sqrt{1-c^2 x^2}-\frac{1}{4} b d \sin ^{-1}(c x)+\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{i d \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}+d \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )+\frac{1}{2} (i b d) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i \sin ^{-1}(c x)}\right )\\ &=-\frac{1}{4} b c d x \sqrt{1-c^2 x^2}-\frac{1}{4} b d \sin ^{-1}(c x)+\frac{1}{2} d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{i d \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}+d \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-\frac{1}{2} i b d \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )\\ \end{align*}
Mathematica [A] time = 0.118707, size = 99, normalized size = 0.82 \[ -\frac{1}{4} d \left (2 i b \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )+2 a c^2 x^2-4 a \log (x)+b c x \sqrt{1-c^2 x^2}+b \sin ^{-1}(c x) \left (2 c^2 x^2-4 \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-1\right )+2 i b \sin ^{-1}(c x)^2\right ) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.158, size = 178, normalized size = 1.5 \begin{align*} -{\frac{da{c}^{2}{x}^{2}}{2}}+da\ln \left ( cx \right ) -{\frac{i}{2}}bd \left ( \arcsin \left ( cx \right ) \right ) ^{2}-{\frac{dbcx}{4}\sqrt{-{c}^{2}{x}^{2}+1}}-{\frac{db\arcsin \left ( cx \right ){c}^{2}{x}^{2}}{2}}+{\frac{bd\arcsin \left ( cx \right ) }{4}}+db\arcsin \left ( cx \right ) \ln \left ( 1-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) +db\arcsin \left ( cx \right ) \ln \left ( 1+icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) -idb{\it polylog} \left ( 2,-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) -idb{\it polylog} \left ( 2,icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{2} \, a c^{2} d x^{2} + a d \log \left (x\right ) - \int \frac{{\left (b c^{2} d x^{2} - b d\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{a c^{2} d x^{2} - a d +{\left (b c^{2} d x^{2} - b d\right )} \arcsin \left (c x\right )}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - d \left (\int - \frac{a}{x}\, dx + \int a c^{2} x\, dx + \int - \frac{b \operatorname{asin}{\left (c x \right )}}{x}\, dx + \int b c^{2} x \operatorname{asin}{\left (c x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (c^{2} d x^{2} - d\right )}{\left (b \arcsin \left (c x\right ) + a\right )}}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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